evaluate tan15° tan25° tan60° tan65° tan75°- tan30°
Answers
Answered by
2
Answer:
Step-by-step explanation:
{ tan15° tan25° tan60° tan65° tan75°}- tan30°
=> { tan15° tan25° tan60° tan(90 - 25)° tan(90 - 15)° } - tan 30°
- Since, tan(90 - Ф) = cotФ
=> {tan15° tan 25° tan60° cot25° cot15°} - tan 30°
- cot Ф = 1/ TanФ
=> {tan15° tan25° tan60° (1/ tan15°) (1/ tan 25°)} - tan 30°
=> {tan60°} - tan 30°
We know that,
- tan 60 = √3
- tan 30 = 1/ √3
=> √3 - 1/ √3
=> (3 - 1)/ √3
=> 2/ √3
Hope this helps!
Similar questions