Evaluate tan²60+4sin²45+3sec²30+5cos90 / cosec30+sec60-cot²30
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Answered by
11
tan60 = √3
sin45 = 1/√2
sec30 = 2/√3
cos90 = 0
cosec30 = 2
sec60 = 2
cot30 = √3
Now A.T.Q
[tex] \frac{( \sqrt{3})^2+4*( \frac{1}{ \sqrt{2} })^2+3*( \frac{2}{ \sqrt{3} })^2 +0 }{2+2-( \sqrt{3})^2 } [/tex]
3+ 2 + 4/ 1 = 9
sin45 = 1/√2
sec30 = 2/√3
cos90 = 0
cosec30 = 2
sec60 = 2
cot30 = √3
Now A.T.Q
[tex] \frac{( \sqrt{3})^2+4*( \frac{1}{ \sqrt{2} })^2+3*( \frac{2}{ \sqrt{3} })^2 +0 }{2+2-( \sqrt{3})^2 } [/tex]
3+ 2 + 4/ 1 = 9
Answered by
1
Answer:
9
Step-by-step explanation:
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