Question

evaluate tan30sin30+cos²60sin²90tan²60-2tan45cos²theeta.sin90​

Answer 1

IDK if it is the correct answer for this question cause I solved a similar one in class today but here goes nothing...

Answer:

4/3

Step-by-step explanation:

(1/√3)^2 × 1/2 +1/2×(1)^2 ×(√3)^2 - 2×1×(1)^2×1

1/3×1/2+1/2×1×3-2×1×1×1

1/6+1/2×1×3-2

2+6/12×3-2

8/12 =4/3

Answer 2

Answer:

See here in the last term you have mentioned cos²theeta and that's something can't be here.

so taking theeta as 30° and solving.

Hope it helps.

Mark Brainer.

Thanks.

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Teacher.