Math, asked by praptiborah02, 8 months ago

evaluate- tan35°tan60°tan55°tan30°

Answers

Answered by nikshay456
4

Answer:

Hope my answer helps you mate

  \tan(35)  \times  \tan(60)  \times  \tan(55)  \times  \tan(30)

Step-by-step explanation:

tan35=cot(90-35)=cot55

tan60=cot(90-60)=cot 30

put values above in given expression

as 1/tanØ=cotø

we get 1/tan55 ×1/cot30. × tan55tan30

so your answer is 1 by cancellation

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Answered by satyampawan201pd3781
5

Answer:

1

Step-by-step explanation:

tanΘ=1/cotΘ. tan(90-Θ)=cotΘ

tan35°tan60°tan55°tan30°

=tan(90-55)°tan(90-30)°tan55°tan30°

=cot55°cot30°tan55°30°

=cot55°xcot30°x1/cot55°x1/cot30

=1

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