Math, asked by nishaterum786, 1 year ago

Evaluate tan48.tan16.tan42.tan74

Answers

Answered by suryansh060
2
Hey mate here is yr answe
Tan48.tan(90-48). Tan74.tan(90-74)
Tan48.Cot48. Tan74.Cot74
As we know that tan×cot=1
So answr is 1.
Thanks for asking a question
Answered by dakshsingh6133
3
tan48×tan16×tan42×tan74
cot(90-48)×cot(90-16)×tan42×tan74. (tanA =cot(90-A)

=cot42×cot74×tan42×tan74

=1/tan42×1/tan74×tan42×tan74

=1/tan42×tan42×1/tan74×tan74 cotA = 1/tanA

=1×1
=1 final answer
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