Math, asked by madanvanshita, 8 months ago

evaluate tan60°-tan30°/1+tan60tan30​

Answers

Answered by mokshaa23
0

Answer:

1/√3

Step-by-step explanation:

tan60°-tan30°/1+tan60tan30​

it is in the form of tan(A-B)

tan(A-B)=tanA-tanB/1+tanAtanB  

tan(60-30)°=tan60°-tan30°/1+tan60tan30​

tan30°=√3-1/√3/1+√3*1/√3

        =3-1/√3/1+1

        =2/√3/2

tan30°=1/√3

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