Evaluate: tan7° tan23° tan60° tan67° tan83° + (cots4°/tan36°)+ sin20° sec70°
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There was a slight mistake in your question but I corrected it with the answer
tan7° tan23° tan60° tan67° tan83° + (cots54°/tan36°)+ sin20° sec70°
= tan7° tan23° tan60° cot23° cot7° + (cots54°/cot54°)+ sin20°cosec20°
= tan60° + 1 + 1
= √3 + 2
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