evaluate- tan7°tan23°tan60°tan67°tan 83°
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17
Given, tan7°tan23°tan60°tan67°tan83°
= tan(90°-83°)tan83°tan(90-67°)tan67°tan60°
= cot83°tan83°cot67°tan67°tan60°
= (1/tan83°) × tan83° × (1/tan67°) × tan67°× tan60°
= 1 × 1 × tan60°
= √3 (ans.)
= tan(90°-83°)tan83°tan(90-67°)tan67°tan60°
= cot83°tan83°cot67°tan67°tan60°
= (1/tan83°) × tan83° × (1/tan67°) × tan67°× tan60°
= 1 × 1 × tan60°
= √3 (ans.)
Answered by
6
Answer:
Given, tan7°tan23°tan60°tan67°tan83°
= tan(90°-83°)tan83°tan(90-67°)tan67°tan60°
= cot83°tan83°cot67°tan67°tan60°
= (1/tan83°) × tan83° × (1/tan67°) × tan67°× tan60°
= 1 × 1 × tan60°
= √3 (ans.)Step-by-step explanation:
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