evaluate tan75degree
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We know that Tan(A + B) = (TanA + TanB)/(1-TanATanB)
tan 75° = Tan(45°+ 30°) = (Tan45° + Tan30°)/(1-Tan 45° Tan30°)
tan 75° = (1 + 1 / √3 ) / (1 - 1 /√3)
tan 75° = (√3 + 1 ) / (√3 - 1 )
Hope it helps.....
tan 75° = Tan(45°+ 30°) = (Tan45° + Tan30°)/(1-Tan 45° Tan30°)
tan 75° = (1 + 1 / √3 ) / (1 - 1 /√3)
tan 75° = (√3 + 1 ) / (√3 - 1 )
Hope it helps.....
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