Question

evaluate
${ - 32}^{\binom{2}{5} }$
please solve
​ch- indices (class 9)

Answer 1

Answer:

${ - 32}^{ \frac{2}{5} } =$

$( { - 2}^{5} ) { \frac{2}{5} }$

5 and 5 gets cancelled

${ -2}^{2}$

by squaring the negative symbol turns positive

$4$

Answer 2

${ - 32}^{\binom{2}{5} } = 4$