Question

Evaluate: $\frac{2cos 67\textdegree}{sin 23\textdegree}- \frac{tan 40\textdegree}{cot50\textdegree} - sin 90\textdegree$

Answer 1

Hey mate, here is you answer..........

2cos(90-23)/ sin23 -tan(90-50)/cot50 - sin90

2 sin23/sin23 - cot50/cot50 - 1

[ • cos(90-A) = sinA]

[ • tan(90-A) = cotA]

[ • sin 90 = 1]

Now,

2(1) -1 -1 = 2-1-1 = 2-2 = 0

Hope this helps you ♥️♥️