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5cos²60°+4sec²30°-tan²45°/sin²30°+cos²30°.
cos60°=1/2.
sec30°=2/√3.
tan45°=1.
sin30°=1/2.
cos30°=√3/2.
5cos²60°+4sec²30°-tan²45°/sin²30°+cos²30°=5(1/2)²+4(2/√3)²-(1)²/(1/2)²+(√3/2)².
=5(1/4)+4(4/3)-1/(1/4)+(3/4).
=(5/4)+(16/3)-1/(1/4)+(3/4).
=15+64-12/12/1+3/4. (Because LCM of 4 & 3 is 12).
=79-12/12/4/4.
=67/12/1.
=67/12.
I think this is your answer.
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