Question

Evaluate:-
[tex]\frac{tan^3\theta}{1+tan^2\theta}+\frac{cot^3\theta}{1+cot^2\theta}=\frac{1-2sin^2\thetacos^2\theta}{sin\thetacos\theta}

Answer 1

$\bf{ Refer \: the \ attached \: image}$

Answer 2

Answer:

hope it is helpful to you