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putting the value of the t ratios,
1/√2+2/1-5×1/2×1
= (2+4√2-5√2)/2√2
= (2-√2)/2√2
= {√2(√2-1)}/2√2
= (√2-1)/2
1/√2+2/1-5×1/2×1
= (2+4√2-5√2)/2√2
= (2-√2)/2√2
= {√2(√2-1)}/2√2
= (√2-1)/2
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