Question

Evaluate
$\frac{ \tan(65) }{ \cot(25) }$
​

Answer 1

Here is ur Answer mate:-

Tan 65/ cot 25

tan 65 can be written as

tan(90-65)/cot 25

cot 25/cot 25=1

Hope it helps you

thanks...

Answer 2

Answer:

Question :-

Evaluate

$\frac{ \tan(65°) }{ \cot(25°) }$

${\blue{\underline{\underline{\bold{Answer:-}}}}}$

As we know, cot A = tan (90°-A)

cot 25° = tan(90°-25°) = tan65°

$\frac{ \tan(65°) }{ \cot(25°) } \\ \\ = \frac{ \tan(65°) }{\cot(65°)} \\ \\ = 1$