Math, asked by aman597284, 8 months ago

EVALUATE
integral \sin(2 + 3 log  \: x) by \: x \:  \: dx
note; by = /

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Answered by ojhasweta52
0

2log(x−3)+log(x+2)−6logx = log((x−3)2(x+2)x6). Explanation: 2log(x−3)+ log(x+2)−6logx =log(x−3)2+log(x+2)−logx6  ...

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