Question

evaluate:
$\sin^{2} 60 - \cos ^{2} 30 + \tan^{2} 30$
​

Answer 1

sin 60 = √3/2

cos 30= √3/2

tann30 = 1/√3

therefore

$\sin {}^{2} (60) - \cos {}^{2} (30) + tan {}^{2} (30)$

$= \frac{1}{ 3}$

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Answer 2

we know that

sin 60 =√3/2

cos30= √3/2

and tan30 = 1/√3

$\sin {}^{2} (60) - \cos {}^{2} (30) + \tan {}^{2} (30)$

$= \frac{1}{3}$