Question

evaluate the 27x cube + y cube - z cube + 9xyz​

Answer 1

Answer:

27x^3+y^3-z^3+9xyz

=(3x)^3+y^3+(-z)^3-3×3x×y×(-z)

=(3x+y-z) (3x^3+y^3-z^3-3x×y-y×(-z)-(-z)×3x)

=(3x+y-z) (27x^3+y^3-z^3-3xy+yz+3zx)

Answer 2

Answer:

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