Physics, asked by ishaan875, 1 year ago

evaluate the ∫ (2x+1)³dx

Answers

Answered by Anonymous

HEYA!!

○●▪☆•°▪○●°•☆

by integration we get

firstly let

X=2x+1

now simplfy by integration method:

$\frac{x^{n + 1} }{n + 1}$

so we get

$\frac{ (2x + 1)^{4} }{4} + c$

HOPE IT HELP

☆○●¤°•~☆▪●○•°~

Answered by Anonymous

$<!DOCTYPE html> <html> <head> <style> .headings{ color: green; font-family: cursive; background-color: b </style> </head> <body> <h1 class="headings">Answer...</h1>$

$let I = ∫( {2x + 1)}^{3}dx \\ \: \: \: \: \: \: \: \: \: = \frac{ {2x + 1}^{3 + 1} }{(3 + 1)[ \frac{d}{dx}(2x + 1 ] } + C \\ \: \: \: \: \: \: \: \: \: = \frac{( {2x + 1)}^{4} }{4.2} + C \\ \: \: \: \: \: \: \: \: \: = \frac{ {(2x + 1)}^{4} }{8} + C$

Hope this will help you ❤

Previous Question

Next Question

evaluate the ∫ (2x+1)³dx ​

Answers

evaluate the ∫ (2x+1)³dx