Evaluate the above question.
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Solution :
( 2+3 ) + ( 2 + 3^2) + ( 2 + 3^3 ) + ..........( 2 + 3^11 )
( 2 + 2 + 2+2 ....... + 2) = 11 times +
( 3 + 3^2 + 3 ^3 + ...... + 3^11 ) G.P. of 11 term
so a = 3 and r = 3
Now 2 ( 11) + a (r ^n - 1 ) / r- 1
= 22 + 3 ( 3 ^ 11 - 1 ) / 3 - 1
= 44 + 3 ^ 12 - 3 / 2
Answer = 41 + 3 ^ 12 / 2
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