Question

evaluate the answer​

Answer 1

Answer:

I used the formulae of

(A+b+c) 2=a2+b2+c2+2ab+2bc+2ca

Answer 2

(1+sin∅+cos∅)²

=>1²+sin²∅ + cos²∅ + 2×1×sin∅ + 2 ×sin∅×cos∅ + 2×cos∅×1

=>1+1+2sin∅+2sin∅cos∅ + 2cos∅

=>2+2sin∅+2sin∅cos∅+2cos∅

=>2+2sin∅+sin2∅ + 2cos∅

{by identity :- (a+b+c)² = a²+b²+c²+2ab+2bc+2ac}

other identity used :-

sin²∅+cos²∅ = 1

2sin∅cos∅ = 2sin∅

Cheers!