Math, asked by Tusharambatwar, 8 days ago

evaluate the answer ​

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Answered by rakeshdubey33
0

Answer:

(log 2)^2

Step-by-step explanation:

  • lim (x-> 1) [2^2(x - 1) + 2×2^(x - 1) + 1]/(sin^2 (x-1)

lim (y-> 0) [2^2y + 2×2^y + 1]/(y^2 ×(sin^2 y / y^2)

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