Physics, asked by vmaravinthan2005, 1 day ago

evaluate the definite integral x^2dx from x=3to 2

Answers

Answered by rprasanta708

0

Answer:

Explanation:

∫32x−2dx. Use the power rule for integration to tackle this: ∫xndx=xn+1n+1. =[x−2+1−2+1]32.

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