Question

Evaluate the definite integrals: $\int^3_2 {\frac 1x} \, dx$

Answer 1

Solution:

We know that

$\int \frac{1}{x} dx = log \: x$
$\int^3_2 {\frac 1x} \, dx \\ \\ = \bigg[log \: x\bigg]^\bm3_{2} \\ \\ = log \: 3 - log \: 2$
$\int^3_2 {\frac 1x} \, dx=log3-log2$

Hope it helps you.