evaluate the expression
1/ sec theta - tan theta
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Answered by
0
Let sec@= 5/4
sec@ =5/4
As we know ,
sec@ =h/b =5/4
p=√(5^2-4^2)=3
now, tan@ =p/b =3/4
so, (1 - tan@)/(1 +tan@)
=>(1 -3/4)/(1+3/4)
=>(1/4)/(7/4)=1/7 (answer)
PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER.
=>(1/4)/(7/4)=1/7 (answer)
sec@ =5/4
As we know ,
sec@ =h/b =5/4
p=√(5^2-4^2)=3
now, tan@ =p/b =3/4
so, (1 - tan@)/(1 +tan@)
=>(1 -3/4)/(1+3/4)
=>(1/4)/(7/4)=1/7 (answer)
PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER.
=>(1/4)/(7/4)=1/7 (answer)
Answered by
4
1/sec x =cosx
tanx=din/cosx
cosx - sinx/cosx
taking LCM
cos^2x - sinx/cosx
cosx-sinx. is the answer
tanx=din/cosx
cosx - sinx/cosx
taking LCM
cos^2x - sinx/cosx
cosx-sinx. is the answer
davironi:
thank you so much for helping me can i ask u a question
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