Question

Evaluate the following
06 sin 20° - 8 sin? 20°​

Answer 1

Let the at A be x k

and the B be y k

when the is x−y

Dist=100km

⟾ =5 hours

∴  Dist =S×T

⟾ 100=(x−y)5

⟾ x−y=20⟶(I)

when THE is x+y

⟾ Dist=100km

⟾ t=1 hours

⟾ Dist=ST

⟾ 100=(x+y)1

⟾ x+y=100⟶(II)

⟾ x−y=20

⟾ x+y=100

​⟾ 2x=120

⟾ x=60km/h

⟾ y=40km/h

Answer 2

Answer:

6 sin 20°- 8 sin^320°[sin 3 theta=3 sin theta - 4 sin^3theta] = 2[3 sin 20°-4 sin^3 20°]=2 [sin(3×20°)]2 sin 60°= 2×✓(3)2=✓(3)