Question

Evaluate the following:
1/a+b+c = 1/a + 1/b + 1/c.
Please solve it because I am unable to get the answer.

Answer 1

Answer:

c = -b or a

Step-by-step explanation:

$\frac{1}{a+b+c} - \frac{1}{c} =\frac{1}{a} + \frac{1}{b}\\\\\frac{-(a+b)}{c(a+b+c)} = \frac{a+b}{ab} \\-ab = ac + cb+ c^{2} \\ac+bc+ab+c^{2} = 0$

Using formula of quadratic equation,

c = -(b+a)±√(b²+a²+2ab - 4ab/ 2

c = -(b+a) ± (a-b) / 2

c = -b, a