Question

Evaluate the following 1/i^58​

Answer 1

Step-by-step explanation:

$1 \div( i ^{2} ) ^29 = 1 \div ( - 1)^29 \\ 1 \div - 1 = - 1$

Answer 2

Answer:

1/i^58

=1/(i^4)^14.i^2

=1/(1)^14.(-1) [i^4=1,i^2=-1]

=1/1.(-1)

=1/-1

=-1

Step-by-step explanation:

hope it helps you...