Evaluate the following:
(1) sec 12º.cosec 78° - tan 12º.cot 78°
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Answer:
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Step-by-step explanation:
We know that
cosec(90˚-θ)=secθ and cot(90˚-θ)=tanθ
Then,
sec12˚cosec78˚ - tan12˚cot78˚
=sec12˚cosec(90˚-12˚) - tan12˚cot(90˚-12˚)
=sec12˚sec12˚ - tan12˚tan12˚
=sec²12-tan²12
=1 [sec²θ-tanθ²=1]
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