Question

evaluate the following 3a³ - 6b³ +36 a² b² -12 ab if a = -1 and b=2​ plz solve in long form by method of algebra ​

Answer 1

Answer:

213

Step-by-step explanation:

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Answer 2

$3a³ - 6b³ +36 a² b² -12 ab \\ a = - 1 \: \: b = 2 \\ = 3 ({ - 1})^{3} - 6 ({2})^{3} + 36 ({ - 1}^{2} \times {2}^{2} ) - 12( - 1 \times 2) \\ = - 3 - 48 + 144 + 24 \\ = 117$

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