evaluate the following. (4-³ × 6-³ ÷ 2-³ ) -¹
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We know the corollary: if a+b+c=0 then a3+b3+c3=3abc
Using the above corollary taking a=−15, b=7 and c=8, we have a+b+c=−15+7+8=0 then the value of (−15)3+(7)3+(8)3 is:
(−15)3+(7)3+(8)3=3(−15×7×8)=−2520
Hence, (−15)3+(7)3+(8)3=−2520
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