Math, asked by situn62, 14 days ago

evaluate the following​

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Answered by mshibli
0

Answer:

 = ( \frac{27}{8} ) {}^{ \frac{2}{3} }  -  (\frac{1}{4} ) {}^{ - 2}  +  {5}^{0}

 =(  \frac{3}{2} ) {}^{3}   {}^{ \times }  {}^{ \frac{2}{3} }  - ( \frac{1}{2} ) {}^{2}  { }^{ \times }  {}^{ - 2}  + 1

( \frac{3}{2} ) {}^{2}  - ( \frac{1}{2} ) {}^{2}  {}^{ \times  - 2}  + 1

 \frac{9}{4}  - ( \frac{1}{2} ) {}^{ - 4}  + 1

 =  \frac{9}{4}  -  {2}^{4}  + 1

 \frac{9}{4}   + 16 + 1

 =  \frac{9 + 64 + 4}{4}

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 =  \frac{77}{4}

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