Question

evaluate the following​

Answer 1

Answer:

hey here is your answer

pls mark it as brainliest

Step-by-step explanation:

$(i {}^{18} + (1 \div i) {}^{25} ) {}^{3} \\ so \: here \: i {}^{18} \: can \: be \: represented \: as \: i {}^{16 + 2} \\ so \: we \: know \: that \: value \: of \: i \: for \: multiple \: of \: 4 \: is \: always \: 1 \\ hence \: i {}^{18} = 1 \times ( - 1) = - 1 \\ \\ similarly \: i {}^{25} = i {}^{24 } \times i \\ = 1 \times i = i$

$so \: now \\ ( - 1 + 1 \div i) {}^{3} \\ = ( - i + 1 \div i) {}^{3} \\ = - i + 1 - 3i {}^{2} + 3i \div (i) {}^{3} \\ = - i + 3i + 1 - 3( - 1) \div ( - i) \\ = 2i + (1 + 3) \div - i \\ = 2i + 4 \div - i \\ = 2(i + 2) \div - i \\ = - 2(i + 2) \div i$