Evaluate the following
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1] Given expression is
cot55
o
tan35
o
+
tan12
o
cot78
o
We can rewrite the expression as:
cot(90
o
−35
o
)
tan35
o
+
tan(90
o
−78)
cot78
o
We know that, cot(90
o
−θ)=tanθ and tan(90
o
−θ)=cotθ
∴ The expression becomes,
tan35
o
tan35
o
+
cot78
o
cot78
o
⇒1+1
⇒2
Hence,
cot55
o
tan35
o
+
tan12
o
cot78
o
=2
cot55
o
tan35
o
+
tan12
o
cot78
o
We can rewrite the expression as:
cot(90
o
−35
o
)
tan35
o
+
tan(90
o
−78)
cot78
o
We know that, cot(90
o
−θ)=tanθ and tan(90
o
−θ)=cotθ
∴ The expression becomes,
tan35
o
tan35
o
+
cot78
o
cot78
o
⇒1+1
⇒2
Hence,
cot55
o
tan35
o
+
tan12
o
cot78
o
=2
Answered by
0
Answer:
- will you try photomath it's best for students it have all solving steps so please try
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