Question

evaluate the following

Answer 1

$1 + w + {w}^{2} + {w}^{3} + {w}^{4} ............... {w}^{100} . \\ r = \frac{1}{w} = \frac{w}{ {w}^{2} } = \frac{1}{w} . \\ so \: this \: series \: will \: be \: in \: gp. \\ a = 1 \\ r = \frac{1}{w} \\ n = 101. \\ sn = a( \frac{1 - {r}^{n} }{1 - r} )(r < 1). \\ = > 1( \frac{1 - ( { \frac{1}{w}) }^{101} }{1 - \frac{1}{w} })$


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