Question

evaluate the following:- 5a²+6ab-2a²+2ba-10 when a=-2 and b=3.
please answer​

Answer 1

It will be 3a²+8ba-10 after simplifying.

Now we have to just put up the values.

3(-2)²+8(3)(-2)-10

3(-2)²+8(3)(-2)-1012+ (-48) -10

3(-2)²+8(3)(-2)-10+ (-48) -1012-58

12+ (-48) -10

12-58

-46

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Answer 2

Answer:

Given,

p(x)= 5a²+6ab-2a²+2ba-10

and,

a= -2 and b=3.

Substituting a= -2 and b=3 in p(x),

5a²+6ab-2a²+2ba-10

= 5(-2)²+6(-2)(3)-2(-2)²+2(3)(-2)-10

= 5(4)-36-2(4)-12-10

= 20-36-8-12-10

= 20-66

= -44

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