Question

evaluate the following ​

Answer 1

     

$\sqrt[3]{27}+\sqrt[3]{0.008}+\sqrt[3]{0.064} \\ \\ \Rightarrow\ 3+0.2+0.4 = \bold{3.6} \\ \\ \\ \[[ \sqrt[3]{27}=3\ \ ; \ \ \sqrt[3]{0.008}=0.2\ \ ; \ \ \sqrt[3]{0.064}=0.4]$

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Answer 2

Answer:

Step-by-step explanation:

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