Question

Evaluate the following.
a. 70% of 2 days (express as hours)
b. 25.5% of 65
C.
17% of 85
d. 45% of 1 hour (express as minutes)
e. 12.5% of 455 kg
f.
22
22.
2%
% of 60​

Answer 1

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${\huge {\boxed{\color{violet}{\bf{ Solution :}}}}}$

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• (a) 70°/• of 2 days ( express as hours )

$\\\sf (a) \: ⧴ \: \frac{70}{100} \: \times 2 \: \times \: 24 \: hours \\\\\sf = \frac{70}{100} \times 48 \: hours \\\\ \sf = \frac{7}{10} \times 48 \: hours \\ \\ \sf = \frac{336}{10} \: hours \: \\\\\sf= \: 33.6 \: hours$

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• (b) 25.5 °/• of 65

$\sf (b) \: ⧴ \: \frac{25.5}{100} \times 65 \\\\\sf = 0 : 255 \times 65 \\\\\sf = 1.6575 \\\\\sf = \frac{1625}{1000}$

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• (c) 17 °/• of 85

$\sf (c) \: ⧴ \: \: \sf \frac{17}{100} \times 85 \\\\\sf = \frac{1445}{100} \\\\\sf = 14.45$

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• (d) 45%. of 1 hour ( express as minutes )

$\sf(d) \: ⧴ \: \frac{45}{100} \times 1 \: hour \\\\\sf = \frac{45}{100} \times 60 \: min \\\\\sf = \frac{2700}{100} \: min \\\\\sf = 27 \: min$

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• (e) 12.5% of 455 kg

$\sf(e) \: ⧴ \: \frac{12.5}{100} \times 455 \: kg \\\\\sf = \frac{5687.5}{100} \: kg \\\\\sf = 56.875 \: kg$

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• (f) 45/2 % of 60

$\sf(f) \: ⧴ \: \frac{45}{2 \times 100} \times 60 = 30 \\\\\sf = \frac{1350}{100} \\\\\sf = 13.50$

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