Question

Evaluate the following at X=-1 y=-2 z=0 (X+y+z)(X+y - z) - X2 y - y2 z +xz2 -4xy ​

Answer 1

Answer:

Given:

x=1

y=2

z=0

Solution:

(x+y+z)(x+y+z)

(1+2+0)(1+2+0)

(3)(3)

9

=9- X2y -y2z + xz2 - 4xy

=9- (1×(2)×2) -(2×(2)×0) + (1×0×(2)) - 4×(1)×(2)

=9 - (4)-(0)+(0)-(8) *

=9 - 4 -8

=-3 ANS...

* 0 0 has been cut because one is plus and minus.Ex:

+y -y and answer will be 0.

Please mark as brainliest. Hope you will like it.

Answer 2

Answer:

Hope it helps u prenu bro ☺️