Question

evaluate the following by using a suitable identity:(10.1)^2

Answer 1

(10+0.1)^2
using identity-(a+b)^2=a^2+2ab+b^2
10^2+2+0.1^2
100+2+0.01
102.01

Answer 2

Heya ✋

Let see your answer !!!!


$(10.1) ^{2} \\ = (10 + 0.1) ^{2} \\ = (10) ^{2} + (0.1) ^{2} + 2 \times 10 \times \\ 0.1 \\ = 100 + 0.01 + 2 \\ = 102.01$



Thanks :))))