Question

Evaluate the following by using identity - 1 (a+b)^2=a^2+ 2ab +b^2(8.1)^2

Answer 1

Hey friend,
Here is the answer you were looking for:
$(8.1)^{2} \\ \\ = (8 + 0.1)^{2} \\ \\ using \: the \: identity \\ {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ \\ = {(8)}^{2} + {(0.1)}^{2} + 2 \times 8 \times 0.1 \\ \\ = 64 + 0.01 + 1.6 \\ \\ = 65.61$

Hope this helps!!!

@Mahak24

Thanks...
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