Question

Evaluate the following by using identity-1.
(i) (101)^2​

Answer 1

Answer:

(101)^2

101)^2= (100+1)^2

a = 100 b = 1

{(a+b)^2 = a^2+b^2+2ab}=(100)^2+(1)^2+2(100)(1)

10000+1+200

=10201 Answer ...

Hope ! answer is helpful for you....