Question

Evaluate the following by using identity -1
$(101)^{2}$
fast

Answer 1

Heya!

Here is your answer:

(101)²

By using identity

(a+b)²= a²+ b²+ 2ab

(100+1)²

= (100)²+ (1)²+ 2×100×1

= 10000 + 1 + 200

= 10201

:)

Answer 2

(101)whole square 2
=(100+1)whole square. Its identity is(a+b)whole square =a square +2 a b +b square
=100 square +2 (100) (1)+1 square
=10000+200+1
=10201
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