evaluate the following by using identity 2
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Answered by
1
(19.9)^2
= (20 - 0.1)^2
here, we use the identity ,
(a - b)^2 = a^2 - 2ab + b^2
where, a = 20 and b = 0.1
so, 20^2 - 2*20*0.1 + 0.1^2
= 400 - 4 + 0.01
hence, 396.01
= (20 - 0.1)^2
here, we use the identity ,
(a - b)^2 = a^2 - 2ab + b^2
where, a = 20 and b = 0.1
so, 20^2 - 2*20*0.1 + 0.1^2
= 400 - 4 + 0.01
hence, 396.01
Answered by
0
Answer:
hi mate this is you answer
Step-by-step explanation:
in explanation
(19+0.9)² / (20-0.1/)²
biggest no. is (20- 0.1)²
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