Evaluate the following.
cos 45º
(1)
sin 45° + cos 45º
(ii)
sec 30° + cosec 60°
200
0
0600
Answers
Answered by
6
Answer:
cos 45º = 1/√2
sin 45° + cos 45º = 1/√2+1/√2 = 2/√2 = √2
sec 30° + cosec 60° = 2/√3+2 =2(1/√3+1)
Answered by
1
cos45°=1/root 2
sin45°+cos45°=1/root2 +1/root2 =2/root2=root2
sec30°+cosec60°=2/root3 +2 =2(1/root 3 +1)
Similar questions