Math, asked by syogini37, 10 months ago

Evaluate the following.
cos 45º
(1)
sin 45° + cos 45º
(ii)
sec 30° + cosec 60°
200
0
0600​

Answers

Answered by Thinker47
6

Answer:

cos 45º = 1/√2

sin 45° + cos 45º = 1/√2+1/√2 = 2/√2 = √2

sec 30° + cosec 60° = 2/√3+2 =2(1/√3+1)

Answered by JCSPRANI
1

cos45°=1/root 2

sin45°+cos45°=1/root2 +1/root2 =2/root2=root2

sec30°+cosec60°=2/root3 +2 =2(1/root 3 +1)

Similar questions