Math, asked by jeff77, 6 months ago

evaluate the following cos37÷sin53

Answers

Answered by yoggeish

0

Answer:

1

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Answered by VimalaDarshani

2

Answer:

cos 37 / sin 53 = cos 37 / cos ( 90 - 53 )

=cos 37 / cos 37 = 1 //

[ sin theta = cos ( 90 - theta ) ]

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