Evaluate the following equation with the help of identity :
Sin cube theta minus cos cube theta
÷ sintheta minus cos theta c
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a³-b³=(a-b)(a²+b²+ab)
using this Identity in the equation:
sin³x-cos³x/sinx-cosx = {(sinx-cosx)(sin²x+cos²x+sinxcosx)}/(sinx-cosx)= (1+sinxcosx)
using this Identity in the equation:
sin³x-cos³x/sinx-cosx = {(sinx-cosx)(sin²x+cos²x+sinxcosx)}/(sinx-cosx)= (1+sinxcosx)
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This is your answer bro.
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