Question

evaluate the following expression according to operator precedence used in c, 10-3%8+6/4

Answer 1

10-3%8+6/4

10-3+6/4

10-3+1

7+1

8

Answer 2

When more than one operator is used in the expression, Operator precedence helps in determining which operator is used first.

So the expression is evaluated as:

The given expression is 10-3%8+6/4

• Firstly the '%' operator is used from left to right and the expression after evaluation becomes:

          $10-3+6/4$

• Then further the '/' operator is used from left to right and the expression after evaluation becomes:
•   $10-3+1$

• Then the '-' operator is used from left to right and the expression after evaluation becomes:

•   $7+1$

• At last, the final answer become

           $8$

So after, evaluating the expression the final answer becomes 8.