Question

evaluate the following for a=5,b=(-4),c=10
${a}^{2} - {b}^{2} + {c}^{2}$


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Answer 1

Answer:

(a+b+c)=10;a

2

+b

2

+c

2

=38 & a

3

+b

3

+c

3

=160

(a+b+c)

2

=a

2

+b

2

+c

2

+2(ab+bc+ac)⇒

2

100−38

=ab+bc+ca

⇒ab+bc+ca=31

As a

3

+b

3

+c

3

−3abc=(a+b+c)[a

2

+b

2

+c

2

−ab−bc−ca]

160−3abc=10[38−31]

⇒

3

160−70

=abc⇒abc=30

Answer 2

Answer:

Take a look at the pic

Step-by-step explanation:

that is the answer