Math, asked by RuokPS999, 5 hours ago

evaluate the following for p = -1,q = -3,r = 7: (a) p^3+pqr-pr^2 ( tell by process)​

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Answered by Hippocrate
3

 \bf\huge\underline{\underline{ Given :- }}

  • p = - 1

  • q = -3

  • r = 7

 \bf\huge\underline{\underline{ To \: Find:- }}

  • p³ + pqr - pr

 \bf\huge\underline{\underline{ Answer :- }}

  • p³ + pqr - pr

putting the values of p , q and r ,

  •   \red{\implies} (-1)³ + (-1)(-3)7 -(-1)7²

  •   \red{\implies} -1 + 21 + 49

  •   \red{\implies} 69

 \rule{10cm}{0.05cm}

[tex] \bf\huge\underline{\underline{ Formulas \: used:- }} [/tex

  • (-a)² = a²

  • (-a)³ = -a

  • (-a)(-b) = ab

  • (+a)(-b) = -ab

Answered by vvsbss1705
1

p³+pqr-pr²

=(-1)³+(-1)×(-3)×7-(-1)×7²

=(-1)+3×7+1×7²

=(-1)+21+49

=(-1)+70

=69

Answer:69

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